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Figure 3 19. Determining whether at least one of three comparisons is true As you might imagine, you can keep right on going, chaining as many || operations as you like. So in the following sample, we re testing whether at least one of five comparisons is valid. So as Figure 3 20 displays, even though just the second and fourth comparison are valid, which is to say return true, overall the chained || expressions return true: var muffin = { oatFlour: [1/3, "cup"], barleyFlour: [1/3, "cup"], pastryFlour: [1 + 1/3, "cup"], freshlyGroundNutmeg: [1/4, "tsp"], saigonCinnamon: [1/2, "tsp"], seaSalt: [1/4, "tsp"], soda: [1, "tsp"], tartar: [1, "tsp"], mapleBrownCow: [1 + 1/2, "cup"], boysenberries: [2, "cup"], choppedPecans: [1/3, "cup"] }; muffin.mapleBrownCow[0] > muffin.boysenberries[0] || muffin.oatFlour[0] !== muffin.barleyFlour[0] || muffin.freshlyGroundNutmeg[0] >= muffin.saigonCinnamon[0] || muffin.choppedPecans[0] <= muffin.mapleBrownCow[0] || muffin.pastryFlour[0] === muffin.barleyFlour[0]; // true

Next, you write a master program that will call each of the subprograms in the required order A simple master program will cycle through the programs one after another when each of the programs completes or a particular event has occurred, such as pressing touch sensor Then, you can go to the other extreme and have a master program that not only advances automatically but allows for the user to navigate the list of programs and run a program out of order if needed Master programs can be simple or complicated; it just depends on what your team needs and wants to do I would recommend having some form of a master program to help speed up the process for program selection; this can be a key factor in saving valuable time at an event.

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So || is pretty lenient just one of two or more chained || has to return true for the whole shebang to return true. && on the other hand, is very strict. Every comparison in a chain of && expressions must be valid for the chain to return true as a whole. So as Figure 3 21 illustrates, even though the first and last two comparisons are true, since the third is false the chain of && expressions return false. So we re asking JavaScript all five comparisons are true, not whether most of them are true. var muffin = { oatFlour: [1/3, "cup"], barleyFlour: [1/3, "cup"], pastryFlour: [1 + 1/3, "cup"], freshlyGroundNutmeg: [1/4, "tsp"], saigonCinnamon: [1/2, "tsp"], seaSalt: [1/4, "tsp"], soda: [1, "tsp"], tartar: [1, "tsp"], mapleBrownCow: [1 + 1/2, "cup"], boysenberries: [2, "cup"], choppedPecans: [1/3, "cup"] }; muffin.mapleBrownCow[0] < muffin.boysenberries[0] && muffin.oatFlour[0] === muffin.barleyFlour[0] && muffin.freshlyGroundNutmeg[0] >= muffin.saigonCinnamon[0] && muffin.choppedPecans[0] <= muffin.mapleBrownCow[0] && muffin.pastryFlour[0] > muffin.barleyFlour[0]; // false

Public Class Person Dim _id As Integer Dim _idRole As Integer Dim _lastName As String Dim _firstName As String Public Property ID() As Integer

Figure 3 21. Determining whether all five comparisons are true Let s make && happy and change the third comparison not less than to less than. As Figure 3 22 displays, since all five comparisons are true, overall the && chain returns true. Hurray! var muffin = { oatFlour: [1/3, "cup"], barleyFlour: [1/3, "cup"], pastryFlour: [1 + 1/3, "cup"], freshlyGroundNutmeg: [1/4, "tsp"], saigonCinnamon: [1/2, "tsp"], seaSalt: [1/4, "tsp"], soda: [1, "tsp"], tartar: [1, "tsp"], mapleBrownCow: [1 + 1/2, "cup"], boysenberries: [2, "cup"], choppedPecans: [1/3, "cup"] }; muffin.mapleBrownCow[0] < muffin.boysenberries[0] && muffin.oatFlour[0] === muffin.barleyFlour[0] && muffin.freshlyGroundNutmeg[0] < muffin.saigonCinnamon[0] && muffin.choppedPecans[0] <= muffin.mapleBrownCow[0] && muffin.pastryFlour[0] > muffin.barleyFlour[0]; // true

Also, having a master program can be one of the important programming items that judges look for during technical reviews If you have developed a master program, be sure to point this out to your technical judges and be ready to explain how it works and why you have it..

Get Return _id End Get Set(ByVal value As Integer) _id = value End Set End Property Public Property IDRole() As Integer Get Return _idRole End Get Set(ByVal value As Integer) _idRole = value End Set End Property Public Property LastName() As String Get Return _lastName End Get Set(ByVal value As String) _lastName = value End Set End Property Public Property FirstName() As String Get Return _firstName End Get Set(ByVal value As String) _firstName = value End Set End Property End Class Public Class Role Dim _id As Integer Dim _roleDescription As String Public Property ID() As Integer Get

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